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Knowledgecenter: Center of Gravity and Torque
How to use torque hinges for monitors
KnowledgeTorque Hinges
FAQ
If flap or door has an consistent density like the figure on the right the center of gravity will be its center. In this case X1=L1÷2.
The picture above is the formula for calculating the maximum moment. Moment depends on opening angle, and horizontal distance of rotational center to "center of gravity".
If multiple hinges/stays are used, total torque will be values multiplied by its quantity
Click here for FREE STOP tools
Click here for SOFT CLOSE tools
To calculate an L-shaped flap's center of gravity, first divide the shape into two simple shapes and calculate each's center of gravity. Then combine the two by adding them together. *The same concept applies where a mirror is attached to a lid, whereeach may have separate centers of gravity. Let's see an example case where an L-shaped flap is divided into 2 pieces.
Height L1*
Thickness t1*
Please input negative values if the centre of gravity is lower than the rotational centre/axis.
Unit length is "cm", to make it easer to understand.
Weight m1
X1 axial distance
cm
Y1 axial distance
Distance to center of gravity G1
Angle formed by G1 and X axis
°
Moment at A
X1 direction
kgf・cm
Y1 direction
Height L2*
Thickness t2*
Weight m2
X2 axial distance
Y2 axial distance
Distance to center of gravity G2
Angle formed by G2 and X axis
Moment at B
X2 direction
Y2 direction
Total Weight
kg
Center of gravity on X axis
mm
Center of gravity on Y axis
Distance of rotational center to total center of gravity
Angle formed by G and X axis
3 places of decimals will be rounded.
If the center of gravity cannot be calculated as the flap/door is already installed, the required torque can instead be calculated by use of a spring scale. As per the chart below, you need to measure the value o the spring scales and distance of otational center (axis) to the scales' measuring point. L1 × F1 =Flap/door moment Max. value of L1 × F1 =Max. flap/ door moment
If L1 is 100cm, and F1is 2.5kg, flap/door moment will be formulated as, 100cm x 2.5kg = 250kgf・cm In this case, you need over 250kg・cm(=24.5 N・m) of torque for Free Stop. It means "hinge/stay torque ≧ 250kg・cm(=24.5 N・m)".
Notes: It will be difficult to calculate center of gravity if something is attached to a flap/door. In this case, you first need to make a rough estimate of weight and center of gravity, and select hinge/stay tentatively. A correct torque can be found by using the method above after assembling. This means you can select appropriate hinges/stays.
There must be a shaft center generating torque in rotational center.
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